How many pounds of a 5% bleach solution are needed to obtain 1 pound of chlorine?

Study for the Indiana Water Operator Test. Utilize flashcards and multiple choice questions, with each question offering hints and detailed explanations. Prepare confidently for your certification exam!

Multiple Choice

How many pounds of a 5% bleach solution are needed to obtain 1 pound of chlorine?

Explanation:
To determine how many pounds of a 5% bleach solution are required to yield 1 pound of chlorine, it's important to understand the concentration of the bleach solution. A 5% bleach solution means that 5% of the solution's weight is pure chlorine. To find out how much total solution contains 1 pound of chlorine, you can use the formula for concentration: \[ \text{Amount of chlorine} = \text{Total weight of solution} \times \text{Concentration} \] In this case, you know that the concentration is 5%, or 0.05 in decimal form. You can set up the equation as follows: \[ 1 \text{ pound of chlorine} = \text{Total weight of solution} \times 0.05 \] Now, rearranging the equation to solve for the total weight of the solution gives: \[ \text{Total weight of solution} = \frac{1 \text{ pound of chlorine}}{0.05} \] Calculating this gives: \[ \text{Total weight of solution} = 20 \text{ pounds} \] Therefore, to obtain 1 pound of chlorine, you need to use 20 pounds

To determine how many pounds of a 5% bleach solution are required to yield 1 pound of chlorine, it's important to understand the concentration of the bleach solution. A 5% bleach solution means that 5% of the solution's weight is pure chlorine.

To find out how much total solution contains 1 pound of chlorine, you can use the formula for concentration:

[

\text{Amount of chlorine} = \text{Total weight of solution} \times \text{Concentration}

]

In this case, you know that the concentration is 5%, or 0.05 in decimal form. You can set up the equation as follows:

[

1 \text{ pound of chlorine} = \text{Total weight of solution} \times 0.05

]

Now, rearranging the equation to solve for the total weight of the solution gives:

[

\text{Total weight of solution} = \frac{1 \text{ pound of chlorine}}{0.05}

]

Calculating this gives:

[

\text{Total weight of solution} = 20 \text{ pounds}

]

Therefore, to obtain 1 pound of chlorine, you need to use 20 pounds

Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy